Integrand size = 24, antiderivative size = 333 \[ \int \frac {\cos ^4(c+d x)}{(a+i a \tan (c+d x))^8} \, dx=\frac {33 x}{2048 a^8}+\frac {i a^2}{80 d (a+i a \tan (c+d x))^{10}}+\frac {i a}{48 d (a+i a \tan (c+d x))^9}+\frac {3 i}{128 d (a+i a \tan (c+d x))^8}+\frac {5 i}{224 a d (a+i a \tan (c+d x))^7}+\frac {5 i}{256 a^2 d (a+i a \tan (c+d x))^6}+\frac {21 i}{1280 a^3 d (a+i a \tan (c+d x))^5}+\frac {3 i}{256 a^5 d (a+i a \tan (c+d x))^3}+\frac {7 i}{512 d \left (a^2+i a^2 \tan (c+d x)\right )^4}-\frac {i}{4096 d \left (a^4-i a^4 \tan (c+d x)\right )^2}+\frac {45 i}{4096 d \left (a^4+i a^4 \tan (c+d x)\right )^2}-\frac {11 i}{4096 d \left (a^8-i a^8 \tan (c+d x)\right )}+\frac {55 i}{4096 d \left (a^8+i a^8 \tan (c+d x)\right )} \]
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Time = 0.28 (sec) , antiderivative size = 333, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {3568, 46, 212} \[ \int \frac {\cos ^4(c+d x)}{(a+i a \tan (c+d x))^8} \, dx=-\frac {11 i}{4096 d \left (a^8-i a^8 \tan (c+d x)\right )}+\frac {55 i}{4096 d \left (a^8+i a^8 \tan (c+d x)\right )}+\frac {33 x}{2048 a^8}+\frac {3 i}{256 a^5 d (a+i a \tan (c+d x))^3}-\frac {i}{4096 d \left (a^4-i a^4 \tan (c+d x)\right )^2}+\frac {45 i}{4096 d \left (a^4+i a^4 \tan (c+d x)\right )^2}+\frac {21 i}{1280 a^3 d (a+i a \tan (c+d x))^5}+\frac {i a^2}{80 d (a+i a \tan (c+d x))^{10}}+\frac {7 i}{512 d \left (a^2+i a^2 \tan (c+d x)\right )^4}+\frac {5 i}{256 a^2 d (a+i a \tan (c+d x))^6}+\frac {i a}{48 d (a+i a \tan (c+d x))^9}+\frac {3 i}{128 d (a+i a \tan (c+d x))^8}+\frac {5 i}{224 a d (a+i a \tan (c+d x))^7} \]
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Rule 46
Rule 212
Rule 3568
Rubi steps \begin{align*} \text {integral}& = -\frac {\left (i a^5\right ) \text {Subst}\left (\int \frac {1}{(a-x)^3 (a+x)^{11}} \, dx,x,i a \tan (c+d x)\right )}{d} \\ & = -\frac {\left (i a^5\right ) \text {Subst}\left (\int \left (\frac {1}{2048 a^{11} (a-x)^3}+\frac {11}{4096 a^{12} (a-x)^2}+\frac {1}{8 a^3 (a+x)^{11}}+\frac {3}{16 a^4 (a+x)^{10}}+\frac {3}{16 a^5 (a+x)^9}+\frac {5}{32 a^6 (a+x)^8}+\frac {15}{128 a^7 (a+x)^7}+\frac {21}{256 a^8 (a+x)^6}+\frac {7}{128 a^9 (a+x)^5}+\frac {9}{256 a^{10} (a+x)^4}+\frac {45}{2048 a^{11} (a+x)^3}+\frac {55}{4096 a^{12} (a+x)^2}+\frac {33}{2048 a^{12} \left (a^2-x^2\right )}\right ) \, dx,x,i a \tan (c+d x)\right )}{d} \\ & = \frac {i a^2}{80 d (a+i a \tan (c+d x))^{10}}+\frac {i a}{48 d (a+i a \tan (c+d x))^9}+\frac {3 i}{128 d (a+i a \tan (c+d x))^8}+\frac {5 i}{224 a d (a+i a \tan (c+d x))^7}+\frac {5 i}{256 a^2 d (a+i a \tan (c+d x))^6}+\frac {21 i}{1280 a^3 d (a+i a \tan (c+d x))^5}+\frac {3 i}{256 a^5 d (a+i a \tan (c+d x))^3}+\frac {7 i}{512 d \left (a^2+i a^2 \tan (c+d x)\right )^4}-\frac {i}{4096 d \left (a^4-i a^4 \tan (c+d x)\right )^2}+\frac {45 i}{4096 d \left (a^4+i a^4 \tan (c+d x)\right )^2}-\frac {11 i}{4096 d \left (a^8-i a^8 \tan (c+d x)\right )}+\frac {55 i}{4096 d \left (a^8+i a^8 \tan (c+d x)\right )}-\frac {(33 i) \text {Subst}\left (\int \frac {1}{a^2-x^2} \, dx,x,i a \tan (c+d x)\right )}{2048 a^7 d} \\ & = \frac {33 x}{2048 a^8}+\frac {i a^2}{80 d (a+i a \tan (c+d x))^{10}}+\frac {i a}{48 d (a+i a \tan (c+d x))^9}+\frac {3 i}{128 d (a+i a \tan (c+d x))^8}+\frac {5 i}{224 a d (a+i a \tan (c+d x))^7}+\frac {5 i}{256 a^2 d (a+i a \tan (c+d x))^6}+\frac {21 i}{1280 a^3 d (a+i a \tan (c+d x))^5}+\frac {3 i}{256 a^5 d (a+i a \tan (c+d x))^3}+\frac {7 i}{512 d \left (a^2+i a^2 \tan (c+d x)\right )^4}-\frac {i}{4096 d \left (a^4-i a^4 \tan (c+d x)\right )^2}+\frac {45 i}{4096 d \left (a^4+i a^4 \tan (c+d x)\right )^2}-\frac {11 i}{4096 d \left (a^8-i a^8 \tan (c+d x)\right )}+\frac {55 i}{4096 d \left (a^8+i a^8 \tan (c+d x)\right )} \\ \end{align*}
Time = 1.16 (sec) , antiderivative size = 208, normalized size of antiderivative = 0.62 \[ \int \frac {\cos ^4(c+d x)}{(a+i a \tan (c+d x))^8} \, dx=\frac {\sec ^{12}(c+d x) (48510 i+88704 i \cos (2 (c+d x))+69300 i \cos (4 (c+d x))+52800 i \cos (6 (c+d x))+21538 i \cos (8 (c+d x))-2240 i \cos (10 (c+d x))-84 i \cos (12 (c+d x))-22176 \sin (2 (c+d x))-34650 \sin (4 (c+d x))-39600 \sin (6 (c+d x))+27720 \arctan (\tan (c+d x)) (\cos (8 (c+d x))+i \sin (8 (c+d x)))-18073 \sin (8 (c+d x))+2800 \sin (10 (c+d x))+126 \sin (12 (c+d x)))}{1720320 a^8 d (-i+\tan (c+d x))^{10} (i+\tan (c+d x))^2} \]
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Time = 0.74 (sec) , antiderivative size = 197, normalized size of antiderivative = 0.59
method | result | size |
derivativedivides | \(\frac {\frac {i}{4096 \left (\tan \left (d x +c \right )+i\right )^{2}}+\frac {33 i \ln \left (\tan \left (d x +c \right )+i\right )}{4096}+\frac {11}{4096 \left (\tan \left (d x +c \right )+i\right )}-\frac {33 i \ln \left (\tan \left (d x +c \right )-i\right )}{4096}+\frac {7 i}{512 \left (\tan \left (d x +c \right )-i\right )^{4}}+\frac {3 i}{128 \left (\tan \left (d x +c \right )-i\right )^{8}}-\frac {i}{80 \left (\tan \left (d x +c \right )-i\right )^{10}}-\frac {5 i}{256 \left (\tan \left (d x +c \right )-i\right )^{6}}-\frac {45 i}{4096 \left (\tan \left (d x +c \right )-i\right )^{2}}+\frac {1}{48 \left (\tan \left (d x +c \right )-i\right )^{9}}-\frac {5}{224 \left (\tan \left (d x +c \right )-i\right )^{7}}+\frac {21}{1280 \left (\tan \left (d x +c \right )-i\right )^{5}}-\frac {3}{256 \left (\tan \left (d x +c \right )-i\right )^{3}}+\frac {55}{4096 \left (\tan \left (d x +c \right )-i\right )}}{d \,a^{8}}\) | \(197\) |
default | \(\frac {\frac {i}{4096 \left (\tan \left (d x +c \right )+i\right )^{2}}+\frac {33 i \ln \left (\tan \left (d x +c \right )+i\right )}{4096}+\frac {11}{4096 \left (\tan \left (d x +c \right )+i\right )}-\frac {33 i \ln \left (\tan \left (d x +c \right )-i\right )}{4096}+\frac {7 i}{512 \left (\tan \left (d x +c \right )-i\right )^{4}}+\frac {3 i}{128 \left (\tan \left (d x +c \right )-i\right )^{8}}-\frac {i}{80 \left (\tan \left (d x +c \right )-i\right )^{10}}-\frac {5 i}{256 \left (\tan \left (d x +c \right )-i\right )^{6}}-\frac {45 i}{4096 \left (\tan \left (d x +c \right )-i\right )^{2}}+\frac {1}{48 \left (\tan \left (d x +c \right )-i\right )^{9}}-\frac {5}{224 \left (\tan \left (d x +c \right )-i\right )^{7}}+\frac {21}{1280 \left (\tan \left (d x +c \right )-i\right )^{5}}-\frac {3}{256 \left (\tan \left (d x +c \right )-i\right )^{3}}+\frac {55}{4096 \left (\tan \left (d x +c \right )-i\right )}}{d \,a^{8}}\) | \(197\) |
risch | \(\frac {33 x}{2048 a^{8}}+\frac {33 i {\mathrm e}^{-6 i \left (d x +c \right )}}{1024 a^{8} d}+\frac {231 i {\mathrm e}^{-8 i \left (d x +c \right )}}{8192 a^{8} d}+\frac {99 i {\mathrm e}^{-10 i \left (d x +c \right )}}{5120 a^{8} d}+\frac {165 i {\mathrm e}^{-12 i \left (d x +c \right )}}{16384 a^{8} d}+\frac {55 i {\mathrm e}^{-14 i \left (d x +c \right )}}{14336 a^{8} d}+\frac {33 i {\mathrm e}^{-16 i \left (d x +c \right )}}{32768 a^{8} d}+\frac {i {\mathrm e}^{-18 i \left (d x +c \right )}}{6144 a^{8} d}+\frac {i {\mathrm e}^{-20 i \left (d x +c \right )}}{81920 a^{8} d}+\frac {247 i \cos \left (4 d x +4 c \right )}{8192 a^{8} d}+\frac {31 \sin \left (4 d x +4 c \right )}{1024 a^{8} d}+\frac {13 i \cos \left (2 d x +2 c \right )}{512 a^{8} d}+\frac {29 \sin \left (2 d x +2 c \right )}{1024 a^{8} d}\) | \(222\) |
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Time = 0.23 (sec) , antiderivative size = 153, normalized size of antiderivative = 0.46 \[ \int \frac {\cos ^4(c+d x)}{(a+i a \tan (c+d x))^8} \, dx=\frac {{\left (55440 \, d x e^{\left (20 i \, d x + 20 i \, c\right )} - 210 i \, e^{\left (24 i \, d x + 24 i \, c\right )} - 5040 i \, e^{\left (22 i \, d x + 22 i \, c\right )} + 92400 i \, e^{\left (18 i \, d x + 18 i \, c\right )} + 103950 i \, e^{\left (16 i \, d x + 16 i \, c\right )} + 110880 i \, e^{\left (14 i \, d x + 14 i \, c\right )} + 97020 i \, e^{\left (12 i \, d x + 12 i \, c\right )} + 66528 i \, e^{\left (10 i \, d x + 10 i \, c\right )} + 34650 i \, e^{\left (8 i \, d x + 8 i \, c\right )} + 13200 i \, e^{\left (6 i \, d x + 6 i \, c\right )} + 3465 i \, e^{\left (4 i \, d x + 4 i \, c\right )} + 560 i \, e^{\left (2 i \, d x + 2 i \, c\right )} + 42 i\right )} e^{\left (-20 i \, d x - 20 i \, c\right )}}{3440640 \, a^{8} d} \]
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Time = 0.54 (sec) , antiderivative size = 462, normalized size of antiderivative = 1.39 \[ \int \frac {\cos ^4(c+d x)}{(a+i a \tan (c+d x))^8} \, dx=\begin {cases} \frac {\left (- 11433487528543532372369386809707411904921600 i a^{88} d^{11} e^{114 i c} e^{4 i d x} - 274403700685044776936865283432977885718118400 i a^{88} d^{11} e^{112 i c} e^{2 i d x} + 5030734512559154243842530196271261238165504000 i a^{88} d^{11} e^{108 i c} e^{- 2 i d x} + 5659576326629048524322846470805168892936192000 i a^{88} d^{11} e^{106 i c} e^{- 4 i d x} + 6036881415070985092611036235525513485798604800 i a^{88} d^{11} e^{104 i c} e^{- 6 i d x} + 5282271238187111956034656706084824300073779200 i a^{88} d^{11} e^{102 i c} e^{- 8 i d x} + 3622128849042591055566621741315308091479162880 i a^{88} d^{11} e^{100 i c} e^{- 10 i d x} + 1886525442209682841440948823601722964312064000 i a^{88} d^{11} e^{98 i c} e^{- 12 i d x} + 718676358937022034834647170895894462595072000 i a^{88} d^{11} e^{96 i c} e^{- 14 i d x} + 188652544220968284144094882360172296431206400 i a^{88} d^{11} e^{94 i c} e^{- 16 i d x} + 30489300076116086326318364825886431746457600 i a^{88} d^{11} e^{92 i c} e^{- 18 i d x} + 2286697505708706474473877361941482380984320 i a^{88} d^{11} e^{90 i c} e^{- 20 i d x}\right ) e^{- 110 i c}}{187326259667657234388900033490246236650235494400 a^{96} d^{12}} & \text {for}\: a^{96} d^{12} e^{110 i c} \neq 0 \\x \left (\frac {\left (e^{24 i c} + 12 e^{22 i c} + 66 e^{20 i c} + 220 e^{18 i c} + 495 e^{16 i c} + 792 e^{14 i c} + 924 e^{12 i c} + 792 e^{10 i c} + 495 e^{8 i c} + 220 e^{6 i c} + 66 e^{4 i c} + 12 e^{2 i c} + 1\right ) e^{- 20 i c}}{4096 a^{8}} - \frac {33}{2048 a^{8}}\right ) & \text {otherwise} \end {cases} + \frac {33 x}{2048 a^{8}} \]
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Exception generated. \[ \int \frac {\cos ^4(c+d x)}{(a+i a \tan (c+d x))^8} \, dx=\text {Exception raised: RuntimeError} \]
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Time = 1.25 (sec) , antiderivative size = 184, normalized size of antiderivative = 0.55 \[ \int \frac {\cos ^4(c+d x)}{(a+i a \tan (c+d x))^8} \, dx=-\frac {-\frac {27720 i \, \log \left (\tan \left (d x + c\right ) + i\right )}{a^{8}} + \frac {27720 i \, \log \left (\tan \left (d x + c\right ) - i\right )}{a^{8}} + \frac {420 \, {\left (99 i \, \tan \left (d x + c\right )^{2} - 220 \, \tan \left (d x + c\right ) - 123 i\right )}}{a^{8} {\left (\tan \left (d x + c\right ) + i\right )}^{2}} - \frac {81191 i \, \tan \left (d x + c\right )^{10} + 858110 \, \tan \left (d x + c\right )^{9} - 4107195 i \, \tan \left (d x + c\right )^{8} - 11748840 \, \tan \left (d x + c\right )^{7} + 22318590 i \, \tan \left (d x + c\right )^{6} + 29583540 \, \tan \left (d x + c\right )^{5} - 27983550 i \, \tan \left (d x + c\right )^{4} - 19002600 \, \tan \left (d x + c\right )^{3} + 9206235 i \, \tan \left (d x + c\right )^{2} + 3108990 \, \tan \left (d x + c\right ) - 648327 i}{a^{8} {\left (\tan \left (d x + c\right ) - i\right )}^{10}}}{3440640 \, d} \]
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Time = 6.41 (sec) , antiderivative size = 294, normalized size of antiderivative = 0.88 \[ \int \frac {\cos ^4(c+d x)}{(a+i a \tan (c+d x))^8} \, dx=\frac {33\,x}{2048\,a^8}-\frac {\frac {\mathrm {tan}\left (c+d\,x\right )\,66953{}\mathrm {i}}{215040\,a^8}+\frac {17}{105\,a^8}-\frac {9097\,{\mathrm {tan}\left (c+d\,x\right )}^2}{26880\,a^8}+\frac {{\mathrm {tan}\left (c+d\,x\right )}^3\,4279{}\mathrm {i}}{43008\,a^8}-\frac {99\,{\mathrm {tan}\left (c+d\,x\right )}^4}{112\,a^8}-\frac {{\mathrm {tan}\left (c+d\,x\right )}^5\,42537{}\mathrm {i}}{35840\,a^8}+\frac {341\,{\mathrm {tan}\left (c+d\,x\right )}^6}{640\,a^8}-\frac {{\mathrm {tan}\left (c+d\,x\right )}^7\,1969{}\mathrm {i}}{5120\,a^8}+\frac {11\,{\mathrm {tan}\left (c+d\,x\right )}^8}{16\,a^8}+\frac {{\mathrm {tan}\left (c+d\,x\right )}^9\,869{}\mathrm {i}}{2048\,a^8}-\frac {33\,{\mathrm {tan}\left (c+d\,x\right )}^{10}}{256\,a^8}-\frac {{\mathrm {tan}\left (c+d\,x\right )}^{11}\,33{}\mathrm {i}}{2048\,a^8}}{d\,\left ({\mathrm {tan}\left (c+d\,x\right )}^{12}\,1{}\mathrm {i}+8\,{\mathrm {tan}\left (c+d\,x\right )}^{11}-{\mathrm {tan}\left (c+d\,x\right )}^{10}\,26{}\mathrm {i}-40\,{\mathrm {tan}\left (c+d\,x\right )}^9+{\mathrm {tan}\left (c+d\,x\right )}^8\,15{}\mathrm {i}-48\,{\mathrm {tan}\left (c+d\,x\right )}^7+{\mathrm {tan}\left (c+d\,x\right )}^6\,84{}\mathrm {i}+48\,{\mathrm {tan}\left (c+d\,x\right )}^5+{\mathrm {tan}\left (c+d\,x\right )}^4\,15{}\mathrm {i}+40\,{\mathrm {tan}\left (c+d\,x\right )}^3-{\mathrm {tan}\left (c+d\,x\right )}^2\,26{}\mathrm {i}-8\,\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )} \]
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